This chapter systematically studies indefinite and definite integrals of single-variable functions, including the basic concepts of integration, common integration methods, properties and applications of integrals, and their practical applications in geometry and physics.
Indefinite Integrals
Definition of Indefinite Integral
If F(x) is a derivative of f(x), then F(x) is called an antiderivative of f(x), and all antiderivatives of f(x) are denoted as
∫f(x)dx=F(x)+C
where C is a constant.
Basic Integration Formulas
∫xndx=n+1xn+1+C (n=−1)
∫x1dx=ln∣x∣+C
∫exdx=ex+C
∫sinxdx=−cosx+C
∫cosxdx=sinx+C
Properties of Indefinite Integrals
Linearity: ∫[af(x)+bg(x)]dx=a∫f(x)dx+b∫g(x)dx
Substitution Method
Let u=φ(x), then
∫f(φ(x))φ′(x)dx=∫f(u)du
Integration by Parts
∫udv=uv−∫vdu
Definite Integrals
Definition of Definite Integral
If f(x) is continuous on [a,b], then
∫abf(x)dx=n→∞limi=1∑nf(xi∗)Δx
Properties of Definite Integrals
Linearity, additivity over intervals, sign-preserving property
Newton-Leibniz Formula
If F(x) is an antiderivative of f(x), then
∫abf(x)dx=F(b)−F(a)
Integral with Variable Upper Limit
F(x)=∫axf(t)dt, F′(x)=f(x)
Improper Integrals
If the interval of integration is unbounded or the integrand is unbounded in the interval, it is called an improper integral.
Integrals of Common Functions
Rational function integrals: partial fraction decomposition
Trigonometric function integrals: trigonometric identities, substitution
Irrational function integrals: substitution method
Applications of Definite Integrals
Area of a plane figure: S=∫ab∣f(x)∣dx
Arc length of a plane curve: L=∫ab1+[f′(x)]2dx
Volume of a solid of revolution: V=π∫ab[f(x)]2dx
Physical applications: work, center of mass, etc.
Exercises
Compute the indefinite integral ∫(2x3−3x2+1)dx.
Compute the definite integral ∫01xex2dx.
Use integration by parts to compute ∫xcosxdx.
Compute the improper integral ∫1∞x21dx.
Find the area enclosed by the curve y=x2 and the x-axis on [0,1].
Compute the arc length of y=x on [0,4].
Reference Answers
1. Compute the indefinite integral ∫(2x3−3x2+1)dx
Solution: Integrate term by term.
∫2x3dx=42x4=21x4
∫−3x2dx=−x3
∫1dx=x
Answer: 21x4−x3+x+C
2. Compute the definite integral ∫01xex2dx
Solution: Substitute u=x2,du=2xdx.
∫01xex2dx=21∫01eudu=21(e1−e0)=21(e−1)
Answer: 21(e−1)
3. Use integration by parts to compute ∫xcosxdx
Solution: Let u=x,dv=cosxdx, du=dx,v=sinx
∫xcosxdx=xsinx−∫sinxdx=xsinx+cosx+C
Answer: xsinx+cosx+C
4. Compute the improper integral ∫1∞x21dx
Solution: ∫1Ax−2dx=[−x−1]1A=(−A1+1), as A→∞, get 1.
Answer: 1
5. Find the area enclosed by y=x2 and the x-axis on [0,1]
Solution: S=∫01x2dx=31
Answer: 31
6. Compute the arc length of y=x on [0,4]
Solution: L=∫041+[f′(x)]2dx, f′(x)=21x−1/2
1+[f′(x)]2=1+4x1
L=∫041+4x1dx
(You can leave it as is, or further simplify using substitution)
Answer: L=∫041+4x1dx (can be further simplified)